A series circuit consists of a 12V source, a 470ohm resistor(R1), a 330ohm resistor(R2) and a diode. If the diode is reverse biased, what is the value of V(R1) and V(R2)?
Zero.
Here's why:
http://www.allaboutcircuits.com/vol_3/chpt_3/1.html
To answer that question, we need to apply Ohm's Law and Kirchhoff's Voltage Law (KVL). Here are the steps to calculate the values of V(R1) and V(R2):
Step 1: Calculate the total resistance (Rtotal) of the circuit.
- Since the circuit is a series circuit, we can simply add the resistances of R1 and R2.
- Rtotal = R1 + R2
- Rtotal = 470 ohms + 330 ohms
- Rtotal = 800 ohms
Step 2: Calculate the total current (I) flowing through the circuit.
- Using Ohm's Law, we can calculate the current flowing through the circuit.
- I = V / Rtotal
- I = 12V / 800 ohms
- I = 0.015A (or 15mA)
Step 3: Calculate the voltage drop across R1 (V(R1)).
- Since R1 and R2 are connected in series, the current flowing through them will be the same.
- V(R1) = I * R1
- V(R1) = 0.015A * 470 ohms
- V(R1) = 7.05V
Step 4: Calculate the voltage drop across R2 (V(R2)).
- V(R2) = I * R2
- V(R2) = 0.015A * 330 ohms
- V(R2) = 4.95V
So, the value of V(R1) is 7.05V and the value of V(R2) is 4.95V when the diode is reverse biased.
In order to find the values V(R1) and V(R2) in a series circuit with a reverse biased diode, we need to calculate the voltage drops across each component separately.
First, let's determine the total resistance of the circuit:
R(total) = R1 + R2
R(total) = 470Ω + 330Ω
R(total) = 800Ω
Since the diode is reverse biased, it will not allow any current to flow through it, acting as an open circuit. Therefore, the total current (I) flowing through the circuit will be determined solely by the resistors.
Using Ohm's Law (V = I * R), we can find the total current:
I = V(total) / R(total)
I = 12V / 800Ω
I ≈ 0.015A or 15mA
Now, we can determine the voltage drops across each resistor.
V(R1) = I * R1
V(R1) = 0.015A * 470Ω
V(R1) ≈ 7.05V or 7.1V (rounded to one decimal place)
V(R2) = I * R2
V(R2) = 0.015A * 330Ω
V(R2) ≈ 4.95V or 5.0V (rounded to one decimal place)
Therefore, the value of V(R1) is approximately 7.1V, and the value of V(R2) is approximately 5.0V.