A bicycle of mass 14.6 kg and a rider of mass 50kg generate a net force of 12N.How fast are they going after 2.0 seconds?
m = 14.6 + 50 = 64.6 kg
F = 12
a = 12/64.6
distance = (1/2) a t^2 = (1/2) a (4)
assuming speed was zero at the beginning of the problem
To determine the speed of the bicycle and rider after 2.0 seconds, we can use Newton's second law of motion.
Newton's second law states that the net force acting on an object is equal to the product of its mass and acceleration:
F = m * a
We are given the net force (F = 12N) and the total mass of the bicycle and rider (m = 14.6kg + 50kg = 64.6kg). We need to calculate the acceleration (a).
Rearranging the formula, we can solve for acceleration:
a = F / m
Plugging in the values, we get:
a = 12N / 64.6kg
Simplifying the equation, we find that the acceleration is approximately 0.186 m/s².
Now, we can use the kinematic equation:
v = u + a * t
where v is the final velocity, u is the initial velocity (which we'll assume is 0 since we don't have that information), a is the acceleration, and t is the time.
Plugging in the values, we find:
v = 0 + 0.186 m/s² * 2.0s
Simplifying the equation, we find that the final velocity (v) is approximately 0.372 m/s.
Therefore, the bicycle and rider are going approximately 0.372 m/s after 2.0 seconds.