find the vertex of
(x+1)^2-2
To find the vertex of the quadratic equation (x + 1)^2 - 2, we can use the vertex form of a quadratic equation, which is y = a(x - h)^2 + k. The vertex of a quadratic equation is represented by the coordinates (h, k).
Comparing the given equation with the vertex form, we can see that a = 1, h = -1, and k = -2.
Therefore, the vertex of the quadratic equation (x + 1)^2 - 2 is (-1, -2).