Post a New Question

physics...

posted by .

Tarzan swings on a 26.2 m long vine initially inclined at an angle of 39° from the vertical.

(a) What is his speed at the bottom of the swing if he starts from rest?


(b) What is his speed at the bottom of the swing if he starts with an initial speed of 3.26 m/s?

  • physics... -

    (a) Think consewervation of energy
    M*g*H = (1/2) M V^2
    V = sqrt(2 g H)
    H is the elevation decrease.
    H = 26.2 (1 - cos39) = 5.84 m

    (b) M g H = CHANGE in kinetic energy
    g*H = (1/2)[V^2 - 3.26^2]
    Solve for V
    This assumes that Tarzan's initial velocity is along the arc of motion of the swing. There could be some small change if it isn't.

  • physics... -

    where did you get the 3.26 in part b? i don't understand that part really...i get the first part though

  • physics... -

    im sorry im having a off day, i see it now

  • physics... -

    Good

  • physics... -

    wait what would the answer be to part b im not getting the right answer

  • physics... -

    Where did u get 5.84m

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

More Related Questions

Post a New Question