in a proposed telesurgery application the image will be transmitted at 2*10^8m/s ovwe a roundtrip distance of 740km, the compression and decompression process for the images will take a total of 60m/s. what is the largest permissible value for the sources of delay if total round trip delay is to be at most 112ms.
You must mean 60 milliseconds (ms) rather than 60 m/s, which is a speed.
Signal travel time = 740,000 m / 2*10^8 m/s = 3.7*10^-3 s.
Image processing time = 60*10^-3 s
Call the total 60 + 4 = 64 ms.
Other sources of signal delay can be 112 - 64 = 48 ms.