C7H6O3+CH3OH→C8H8O3+H2O
In any experiment, 1.50g of salicyclic acid is reacted with 11.20g of methanol. The yield of methyl salicylate, C8H8O3, is 1.31g. What is the percent yield?
percent is 77.l1%
is this correct?
theoretical yield= 1.50/molmassC7H6O3 * molmassC8H8OH
=1.50/138.12 * 152.14=1.65g
percent yield= 1.31/1.65=.792
check my calcs.
To calculate the percent yield, we can use the formula:
Percent Yield = (Actual Yield / Theoretical Yield) * 100
Given:
Mass of salicylic acid (C7H6O3) = 1.50 g
Mass of methanol (CH3OH) = 11.20 g
Actual yield of methyl salicylate (C8H8O3) = 1.31 g
First, we need to calculate the theoretical yield of methyl salicylate using the balanced chemical equation:
C7H6O3 + CH3OH → C8H8O3 + H2O
From the equation, we can see that the ratio of salicylic acid to methyl salicylate is 1:1. So, the theoretical yield of methyl salicylate would be the same as the mass of salicylic acid used, which is 1.50 g.
Now, we can calculate the percent yield:
Percent Yield = (Actual Yield / Theoretical Yield) * 100
Percent Yield = (1.31 g / 1.50 g) * 100
Percent Yield = 87.33%
Therefore, the correct percent yield is 87.33%, not 77.11%.
To determine the percent yield, we need to compare the actual yield (1.31g) to the theoretical yield, which is the amount of methyl salicylate that would be produced if the reaction proceeded to completion.
First, we need to calculate the theoretical yield of methyl salicylate (C8H8O3). We can do this by using stoichiometry:
1 mol of C7H6O3 reacts with 1 mol of CH3OH, and it produces 1 mol of C8H8O3. Therefore, the molar ratio between salicylic acid (C7H6O3) and methyl salicylate (C8H8O3) is 1:1.
The molar mass of salicylic acid (C7H6O3) is approximately 138.12 g/mol. Therefore, 1.50g of salicylic acid is equal to 1.50 g / 138.12 g/mol = 0.0109 mol.
Since the molar ratio is 1:1, the theoretical yield of methyl salicylate (C8H8O3) is also 0.0109 mol.
Now, we can calculate the theoretical mass of the methyl salicylate:
The molar mass of methyl salicylate (C8H8O3) is approximately 152.15 g/mol. Therefore, the theoretical mass of methyl salicylate is:
0.0109 mol × 152.15 g/mol = 1.66 g
Now, we can calculate the percent yield:
Percent Yield = (Actual Yield / Theoretical Yield) × 100%
= (1.31 g / 1.66 g) × 100%
= 0.789 × 100%
= 78.9%
Therefore, the correct percent yield is approximately 78.9%, not 77.11%.