chemistry
posted by andy .
The value of the equilibrium constant (Kc) as represented by the first chemical equation is 2.70 x 103 at 1200 K. Calculate the value of the equilibrium constant (Kc) for the second equation at the same temperature. Express answer in scientific notation.
F2(g) = 2F(g)
2F(g) = F2(g)

Equation 1 and 2 are just the reverse of ech other. If you have K for one of them, K for the other is just the reciprocal of the first. So if k is 2.7 x 10^3, the reverse is 1/2.70 x 10^3.
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