what is the pressure exerted by 32g of 0xygen(O2) in a 22.0 L container at 30.0`C?

What Law do I use?

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Think of the equations you have learned and which variables you have been given. It helps to keep a list of them in front of you so you can quickly figure it out. Then just plug in. If you have P, V, mass, and T....you're going to use PV=nRT...just solve for P

PV=nRT is an equation you're going to want to just memorize...you'll be using it a lot..

Oh the Ideal Law? Thank you so much!!

no problem :)

To find the pressure exerted by a given amount of substance in a container, we can use the ideal gas law. The ideal gas law states that the pressure (P) of a gas is directly proportional to the number of moles (n) of the gas, the temperature (T) in Kelvin, and inversely proportional to the volume (V) of the container. Mathematically, it can be represented as:

PV = nRT

Where:
P = Pressure
V = Volume
n = Number of moles
R = Ideal gas constant (0.0821 L·atm/(mol·K))
T = Temperature in Kelvin

In this case, we have all the information except for the number of moles (n). So the first step is to calculate the number of moles using the given mass of oxygen (O2) and its molar mass.

The molar mass of oxygen (O2) is 2(atomic mass of oxygen) = 2(16.00 g/mol) = 32.00 g/mol.

Now, we can calculate the number of moles (n) by using the formula:

n = mass / molar mass

Given that the mass of oxygen (O2) is 32g, the number of moles can be calculated as:

n = 32g / 32.00 g/mol

n = 1 mol

Now that we have the number of moles (n), we can proceed to calculate the pressure (P) using the ideal gas law equation.

P = (nRT) / V

Substituting in our known values:
P = (1 mol) (0.0821 L·atm/(mol·K)) (30.0 + 273.15 K) / 22.0 L

Calculating this expression will give us the pressure (P) exerted by 32g of oxygen (O2) in a 22.0 L container at 30.0°C.