how many moles of ethylene reacted if 0.50 mole of water is produced.
C2H4 + 3O2 --- 2CO2 + 2H2O
0.5 mole H2O x (1 mol C2H4/2 mol H2O) = ??
Note that the factor (the part in parentheses) is just the ratio of the coefficients in the balanced equation. Also, note that the factor is placed so that the unit we are converting FROM cancels (in this case it is H2O) and the unit we are converting TO is the unit we keep.
To answer this question, we need to use the balanced chemical equation provided. The coefficients in the balanced equation represent the molar ratios between the reactants and products.
The balanced equation is:
C2H4 + 3O2 → 2CO2 + 2H2O
From the equation, we can see that for every 1 mole of C2H4 (ethylene), 2 moles of H2O (water) are produced.
Given that 0.50 moles of water are produced, we need to determine the number of moles of ethylene that reacted.
Using the molar ratio from the balanced equation, we can set up the following proportion:
(0.50 moles water)/(2 moles water) = (x moles ethylene)/(1 mole ethylene)
Simplifying the proportion:
(0.50 moles water) * (1 mole ethylene)/(2 moles water) = x moles ethylene
Calculating:
x = 0.50/2 = 0.25 moles ethylene
Therefore, 0.25 moles of ethylene reacted to produce 0.50 moles of water.