Post a New Question

Chemistry

posted by .

The value of the equilibrium constant (Kp) as represented by the first chemical equation is 1.02 x 102 at 727 °C. Calculate the value of the equilibrium constant (Kp) for the second equation at the same temperature. Express answer in scientific notation.



2F(g) = F2(g)

F2(g) = 2F(g)

I'm not getting the math here, like how to mortify the first equation to equal it to the second one. [F]/[F]^2 = [F]^2/[F] ?

The answer is 9.8 x 10^-3

  • Chemistry -

    Wait never mind I figured it out.
    1/F = F so 1/102 right?

  • Chemistry -

    right.
    1/k = 1/1.02 x 10^2 = 9.8 x 10^-3

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. Chem

    I am having problems with these two questions. 1.The value of the equilibrium constant (Kp) as represented by the first chemical equation is 1.58 x 102 at 727 °C. Calculate the value of the equilibrium constant (Kp) for the second …
  2. chemistry

    The value of the equilibrium constant (Kc) as represented by the first chemical equation is 2.70 x 10-3 at 1200 K. Calculate the value of the equilibrium constant (Kc) for the second equation at the same temperature. Express answer …
  3. college chemistry

    The value of the equilibrium constant (Kp) as represented by the first chemical equation is 4.57 x 10-2 at 395 °C. Calculate the value of the equilibrium constant (Kp) for the second equation at the same temperature. Express answer …
  4. college chemistry

    At 625 K the value of Kc for the equilibrium represented by the balanced equation is 2.50 x 100. Calculate the value of Kp at the same temperature. Express answer in scientific notation. 2NH3(g) = N2(g)+3H2(g)
  5. college chemistry

    The value of the equilibrium constant, Kc, at a certain temperature is 4.00 x 10-1. Would the reaction as represented by the chemical equation favor reactants or products?
  6. AP CHEMISTRY

    write the equilibrium-constant expression and calculate the value of the equilibrium constant for each of the following reactions at 298 K. (a) NaHCO3(s)<--> NaOH(s) + CO2(g) Answer: Keq = PCO2 (b)Value of the Equilibrium Constant: …
  7. Chemistry

    Need help in AP chemistry on Equilibrium When heated, hydrogen sulfide gas decomposes according to the equation 2 H2S(g) ⇄ 2 H2(g) + S2(g) A 3.40 g sample of H2S(g) is introduced into an evacuated rigid 1.25 L container. The …
  8. Idontgetit

    The value of the equilibrium constant (Kp) as represented by the first chemical equation is 2.00 x 10-2 at 730 K. Calculate the value of the equilibrium constant (Kp) for the second equation at the same temperature. Express answer …
  9. Idontgetit

    At 565 K the value of Kp for the equilibrium represented by the balanced equation is 2.00 x 10-1. Calculate the value of Kc at the same temperature. Express answer in scientific notation. PCl3(g)+Cl2(g) = PCl5(g) ____ x 10 _____
  10. Idontgetit

    At 1650 °C the value of Kc for the equilibrium represented by the balanced equation is 2.38 x 10-1. Calculate the value of Kp at the same temperature. Express answer in scientific notation. CO(g)+H2O(g) = CO2(g)+H2(g) ___ x 10 ____

More Similar Questions

Post a New Question