an electric toy cart has a mass of 6.0 kilograms and a constant acceleration of 0.50 m/s2. How much work does the net force do on the toy cart as the cart travels 8.0 meters?
Screw Physics
The applied force is M*a = 3.0 Newtons.
Multiply that by the distance moved to get the work done on the cart by the outside force (or the motor driving it). The work will be in Joules if the distance is in meters.
To find the work done by the net force on the toy cart, we need to use the formula:
W = Fd
where:
W is the work done (in joules),
F is the net force (in newtons),
and d is the distance traveled (in meters).
First, we need to find the net force acting on the toy cart. We can use Newton's second law of motion, which states that the net force acting on an object is equal to the mass of the object multiplied by its acceleration:
F = ma
Given:
mass (m) = 6.0 kilograms
acceleration (a) = 0.50 m/s^2
Plugging in the values, we get:
F = 6.0 kg * 0.50 m/s^2
F = 3.0 newtons
Now that we know the net force, we can calculate the work done using the given distance of 8.0 meters:
W = Fd
W = 3.0 N * 8.0 m
W = 24 joules
Therefore, the net force does 24 joules of work on the toy cart as it travels 8.0 meters.