80.0 g of iodine (v) oxide reacts with 28.0 g of carbon monoxide determine the mass of iodine
To determine the mass of iodine, we need to use the concept of stoichiometry to determine the molar ratio between iodine(V) oxide (I2O5) and iodine (I2).
1. Start by balancing the chemical equation for the reaction:
I2O5 + 5CO -> I2 + 5CO2
2. Convert the given masses of reactants into moles using their respective molar masses. The molar masses are:
- Molar mass of I2O5 = 2(126.9 g/mol) + 5(16.00 g/mol) = 333.9 g/mol
- Molar mass of CO = 12.01 g/mol + 16.00 g/mol = 28.01 g/mol
Moles of I2O5 = mass of I2O5 / molar mass of I2O5 = 80.0 g / 333.9 g/mol
Moles of CO = mass of CO / molar mass of CO = 28.0 g / 28.01 g/mol
3. Determine the mole ratio of I2O5 to I2 by examining the balanced equation. From the equation, we can see that 1 mole of I2O5 reacts to produce 1 mole of I2.
4. Since the mole ratio is 1:1, the number of moles of I2 produced is equal to the number of moles of I2O5 used.
5. Convert the moles of I2 to mass using the molar mass of iodine (I2), which is 2(126.9 g/mol) = 253.8 g/mol.
Mass of I2 = moles of I2 × molar mass of I2 = moles of I2O5 × molar mass of I2
Mass of I2 = moles of I2O5 × (molar mass of I2 / molar mass of I2O5)
Now, plug in the values to calculate the mass of iodine.
Mass of I2 = (80.0 g / 333.9 g/mol) × (253.8 g/mol / 1 mol)
Mass of I2 ≈ 60.6 g
Therefore, the mass of iodine (I2) produced in the reaction is approximately 60.6 grams.