Calculate the mass percent of methanol, ethanol, and MTBE (answers must be received in that order) that must be present in gasoline to yield a mixture of 1.3 % oxygen by weight.
To calculate the mass percent of methanol, ethanol, and MTBE in gasoline to yield a mixture with 1.3% oxygen by weight, we need to consider the oxygen content of each compound and their respective molecular weights.
First, we need to determine the oxygen content of each compound:
1. Methanol (CH3OH): Methanol contains one oxygen atom, which contributes to its molecular weight of 32.04 g/mol.
2. Ethanol (C2H5OH): Ethanol also contains one oxygen atom, and its molecular weight is 46.07 g/mol.
3. MTBE (C5H12O): MTBE contains one oxygen atom and has a molecular weight of 88.15 g/mol.
Now, let's assume we have a certain mass of gasoline. We need to find the mass of each compound (methanol, ethanol, and MTBE) required to achieve a 1.3% oxygen content.
To do this, we can set up an equation using the oxygen content of each compound and the respective molecular weights:
Let's call the mass of gasoline "x" (in grams).
Mass of methanol = (1.3 / 100) * x
Mass of ethanol = (1.3 / 100) * x
Mass of MTBE = (1.3 / 100) * x
To convert these masses into the respective number of moles, we divide each mass by the compound's molecular weight:
Moles of methanol = Mass of methanol / Molecular weight of methanol
Moles of ethanol = Mass of ethanol / Molecular weight of ethanol
Moles of MTBE = Mass of MTBE / Molecular weight of MTBE
The mass percent of each compound can be calculated by dividing the mass of that compound by the total mass of the mixture (x) and multiplying by 100:
Mass percent of methanol = (Mass of methanol / x) * 100
Mass percent of ethanol = (Mass of ethanol / x) * 100
Mass percent of MTBE = (Mass of MTBE / x) * 100
Substituting the calculated masses, we can calculate the mass percent of each compound.