Calculus
posted by Stuck .
"Evaluate the following indefinite integrals:
"S" (3x^2 2)/(x^3  2x + 1)^3 dx"
We're practicing the substitution rule, and I know how to do it, but I don't know what/how to substitute in this question.
btw: "S" is the integral sign.

substituition for the denominator
giving you du= 3x^22
leaving you with just 1/u^3 then find the anti derivative of that and youll have you answer. Don't forget your c
Respond to this Question
Similar Questions

calculus
We're doing indefinite integrals using the substitution rule right now in class. The problem: (integral of) (e^6x)csc(e^6x)cot(e^6x)dx I am calling 'u' my substitution variable. I feel like I've tried every possible substitution, but … 
Maths
What is the answer for these questions: 1) Indefinite Integrals gcx) = (8 + 39x ^ 3) / x 2) Indefinite Integrals hcu) = sin ^2 (1/8 u) 3) Evaluate x ( 8  5 x ^2) dx Thank you 
single variable calculus  indefinite integrals
integral of (1(sinx)^2))/(cosx)dx i don't know what to make my "u" for usubstitution 
Calc
First make an appropriate substitution and then use integration by parts to evaluate the indefinite integrals: ∫ sinx cos³x e^(1sin²x) dx I was going to substitute u= 1  sin²x, but then i got du = ½ sinxcosx  ½ xdx, so … 
Calc
Use substitution to evaluate the indefinite integral: The integral of [ (sq. root (1 + ln x)) ((ln x)/x) dx] Im confused on what i should substitute u and du for. Thank you so much!! 
calculus
evaluate the following indefinite integrals by substitution & check the result by differentiation. ∫(sin2x)^2 cos2xdx 
Calculus
Use the substitution x=3tan() to evaluate the indefinite integral 93dx/(x^2sprt(x^2+9)) 
calculus
Evaluate the following integrals using the given substitutions. (a) (3x^2 + 10x)dx/(x^3 + 5x^2 + 18 , substitution u = x3 + 5x2 + 18; (b)(14x + 4)cos(7x^2 + 4x)dx,substitution u = 7x^2 + 4x. 
Calculus indefinite integrals
Evaluate the following indefinite integrals using substitution a) ∫ xsqrt(x^27) dx b) ∫ x^(2/3)(1/5x^(5/3)+2)^4 dx 
Math (Integrals)
Find the indefinite integral in two ways. ∫(2x1)^2 dx The first way I used was using the power rule and chain rule with substitution. Let u = 2x  1 du = 2 dx (1/2)∫ u^2 du (Applying power rule) (1/2) * (u^3/3) + C =(2x1)^3/6 …