math problem
posted by Karin .
2^2x1 = 32^x2
2/x  1/2x= 1/2
(2 over x minus 1 over 2x equals 1 over 2)
3/x + 8/x5= 1
(3 over x plus 8 over x minus 5 equals 1)

2/x  1/2x = 1/2
Make a common denominator on the left.
3/2x = 1/2
Crossmultiply.
2x = 6
Divide both sides by 2.
x = 3
Now you try one.
I am not sure what the exponents are in your first problem. If they are 2x1 and x2, rewrite the right side as a power of 2.
2^(2x1) = (2^5)^(x2) = 2^(5x10)
The exponents of 2 must be equal.
2x  1 = 5x  10
3x = 9
x = 3 
x over 4 is equal to negitive 1