Physical Chemistry

posted by .

Assuming that the activation energy is about 111kjmol-1, calculate the fractional variation in the rate constant that would result from a temparature of 323.15 K

  • Physical Chemistry -

    I just would liek to know how to go about calculating it fromt eh equation
    k= Ae-Ea/RT..

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. Chemistry

    During activation energy... A. A catalyst lowers the activation energy by changing the reaction mechanism. B. A catalyst does not change the activation energy. C. A catalyst lowers the activation energy by changing the rate. D. A catalyst …
  2. Chemistry, Arrhenius law

    The rate constant of a first order reaction is 4.60x10^-4/s at 350 degrees Celsius. If the activation energy is 104 kJ/mol, calculate the temp. at which its rate constant is 8.80 x 10^-4/s. So I think that I can use this version of …
  3. chemistry

    Doing review for an exam and I can't find how to do this problem in my notes. 2 SO2 + 2 Cl2 -----> 2 SOCl2 + O2 from a previous problem I solved: rate=k[SO2]^2[Cl2] k = 467.666666... or in sig. figs 467 Energy reaction: T= 25 C …
  4. chemistry

    Doing review for an exam and I can't find how to do this problem in my notes. 2 SO2 + 2 Cl2 -----> 2 SOCl2 + O2 from a previous problem I solved: rate=k[SO2]^2[Cl2] k = 467.666666... or in sig. figs 467 Energy reaction: T= 25 C …
  5. chemistry

    For a certain chemical reaction, the rate constant at 250.0 °C is 0.00383 s-1 and the activation energy is 22.40 kilojoules. Calculate the value of the rate constant at 335.0 °C. a. 0.00513 s-1 b. 0.00946 s-1 c. 0.00787 s-1 d. 0.0224 …
  6. Chemistry

    The rate constant of a particular reaction is halved when the temperature is decreased from 323 K to 273 K. Calculate the activation energy for the reaction.
  7. chemistry

    Values of the rate constant for the decomposition of N2O5 at four different temperatures are as follows: T(K) k(s^-1) 658....2.14*10^5 673....3.23*10^5 688....4.81*10^5 703....7.03*10^5 The activation energy is 1.02*10^2 kJ/mol. Calculate …
  8. chemistry

    The rate constant of a first-order reaction is 4.25 x 10^-4 s^-1 at 350 Celsius. If the activation energy is 103 kJ/mol, calculate the temperature at which its rate constant is 8.75 x 10^-4 s^-1.
  9. physical chemistry

    the rate constant for a reaction at 30 degrees is found to be exactly twice the value at 20 degrees. calculate the activation energy
  10. chemistry

    The first order rate constant for the decomposition of N2O2 of 0Cis 5.2*10/6 per minute. If the activation energy is 6200J/mol, calculate the rate constant at 25C

More Similar Questions