Math

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With time, t, in minutes, the temperature, H, in degrees Celsius, of a bottle of water put in the refrigerator at time t=o is given by
H = 4 + 16e-.02t
How fast is the water cooling initially? After 10 minutes? Include units in your answer

  • Math -

    Do you have a typo?
    Should it not be H = 4 + 16e^(-.02t) ?

    if so, then ....

    dH/dt = - .32e^(-.02t)

    Initially means t = 0
    dH/dt = -.32e^0 = - .32° / minute

    when t=10
    dH/dt = -.32e^(-.2) = -.26° / min

    check my arithmetic

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