pre calc
posted by Danika .
suppose beta is an angle in the second quadrant and tan beta=2. Fine the exact vaule of sin beta and cos beta

draw a rightangled triangle in the second quad
so that tan B = 3/1, that is make the opposite 3 and the adjacent 1, thus the hypotenuse is √10
so y=3, x = 1, r=√10
sinB = 3/√10, cosB = 1/√10
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