how to do (y^36)12= (16n)1/2= (12x^8)1/2= 3y^12/10=
An equation can only have one equal sign. I don't know what you meant.
sorry these are different problems. (y^36)1/2=, (16n)^1/2=, (12x^8)1/2=, and 3y^12?10=
i know they are different problems but i really need your help.please.
To solve each of these equations, we need to apply basic rules of exponents. Let's go through them one by one:
1. (y^36)^12:
Here, we need to raise y^36 to the power of 12. To find the result, we multiply the exponents. So, (y^36)^12 = y^(36 * 12) = y^432.
2. (16n)^(1/2):
This expression involves raising 16n to the power of 1/2. Since 1/2 is the square root, we can simplify it as the square root of 16n. The square root of 16 is 4, and the square root of n is simply n. Therefore, (16n)^(1/2) = 4n.
3. (12x^8)^(1/2):
Similar to the previous example, we need to find the square root of 12x^8. The square root of 12 is not a perfect square, so it remains the same. For x^8, we divide the exponent by 2 since we are finding the square root. Therefore, (12x^8)^(1/2) = 12^(1/2) * x^(8/2) = √12 * x^4.
4. 3y^12/10:
In this expression, we need to simplify 3y^12/10. The exponent 12 belongs to y, and we divide it by 10 since the exponent of y is in the denominator. So, 3y^12/10 is equal to 3 * y^(12/10) = 3y^(6/5).
These are the simplified forms of the given expressions. Remember to apply the rules of exponents correctly to solve similar problems in the future.