NaOH + HCl --> NaCl + H2O
What is the amount of heat absorbed by water? given:
mass: 102.2 grams
specific heat: .9601 cal/g degrees C
You don't have enough information. You may be able to obtain more by looking up the heat of formation of the products and reactants and
delta Hrxn = (sum DH products)-(sum DH reactants)
To calculate the amount of heat absorbed by water, we will use the formula:
q = m * c * ΔT
where:
q = heat absorbed by water
m = mass of water
c = specific heat capacity of water
ΔT = change in temperature
In this case, we are given:
mass of water (m) = 102.2 grams
specific heat capacity of water (c) = 0.9601 cal/g degrees C
However, we are not given the change in temperature (ΔT), so we cannot calculate the exact amount of heat absorbed without that information.
If you have the initial and final temperature of the water, you can calculate the change in temperature (ΔT) by subtracting the initial temperature from the final temperature. Once you have the change in temperature, you can substitute all the values (m, c, and ΔT) into the formula to find the amount of heat absorbed by water (q).