Marshall applies a constant force of 20N to a box and causes it to move at a constant speed of 4m/s. Show that the work he does in moving the box in 6s is 480J.
KE/2v^2=m?
Work done is force times distance moved.
In 6 seconds, at 4m/s the box moves___m
Force times distance = ______
physics
To show that the work done by Marshall in moving the box is 480J, we can use the formula for work:
Work = Force × Distance × cosθ
where:
- Work is the work done (in joules, J)
- Force is the applied force (in newtons, N)
- Distance is the displacement (in meters, m)
- θ is the angle between the direction of the force and the direction of displacement (if the force and displacement are in the same direction, cosθ = 1)
In this case, the force applied by Marshall is 20N and the box moves at a constant speed of 4m/s. Since the box moves at a constant speed, we can assume that there is no acceleration, and therefore the cosine of the angle between the force and displacement is 1.
Now we need to find the distance covered by the box in 6 seconds. Since the box moves at a constant speed, we can use the formula:
Distance = Speed × Time
Distance = 4m/s × 6s = 24m
Substituting the values into the work formula:
Work = 20N × 24m × 1 = 480J
Thus, the work done by Marshall in moving the box in 6 seconds is 480J.