I havent been at school for 8 days due to somthing wrong with my heart, but the teachers gave me work. I have no clue how to do them. I really need help please, There all due tomarrow.
A 2.00L flask is filled with propane gas(C3H8)at 1.00atm and 15C. What is the mass of propane in the flask?
Use PV = nRT.
Remember T is in kelvin. Solve for n = number of moles.
Then n = grams/molar mass
Im still not understanding.
:(
LORD! I hate chemisty
To find the mass of propane in the flask, you need to use the ideal gas law equation, which relates pressure (P), volume (V), temperature (T), and the number of moles of gas (n).
The ideal gas law equation is as follows:
PV = nRT
Where:
P is the pressure in atmospheres (atm)
V is the volume in liters (L)
n is the number of moles of gas
R is the ideal gas constant, which is 0.0821 L·atm/(mol·K)
T is the temperature in Kelvin (K)
First, convert the given temperature from degrees Celsius (°C) to Kelvin (K) by adding 273.15 to it. In this case, 15°C + 273.15 = 288.15 K.
Next, rearrange the ideal gas law equation to solve for the number of moles (n):
n = PV / RT
Substitute the given values into the equation:
P = 1.00 atm
V = 2.00 L
T = 288.15 K
R = 0.0821 L·atm/(mol·K)
Now, you can calculate the number of moles of propane gas:
n = (1.00 atm * 2.00 L) / (0.0821 L·atm/(mol·K) * 288.15 K)
Simplify the equation:
n = 0.07 mol
Since propane gas (C3H8) has a molar mass of approximately 44.1 g/mol, you can calculate the mass of propane in the flask:
Mass = number of moles (n) * molar mass
Mass = 0.07 mol * 44.1 g/mol
Mass = 3.087 g
Therefore, the mass of propane in the flask is approximately 3.087 grams.
Just follow the instructions. I explained R above from your earlier question.
You have P in atmospheres (1 atm), you have Volume (2.00 L), you know R = 0.08206 and T = 273 + 15 = 288 Kelvin.
Solve for n = number of moles.
Then moles = grams/molar mass
You have moles and you have molar mass of propane (about 44 but you need to confirm that), solve for grams.