A 2.00L flask is filled with propane gas(C3H8)at 1.00atm and 15C. What is the mass of propane in the flask?
To find the mass of propane in the flask, we need to use the ideal gas law equation: PV = nRT.
P = pressure (1.00 atm)
V = volume (2.00 L)
n = number of moles of propane
R = ideal gas constant (0.0821 L·atm/(mol·K))
T = temperature (15°C = 15 + 273 = 288 K)
First, let's rearrange the equation to solve for n (number of moles):
n = (PV) / (RT)
Now, substitute the given values into the equation:
n = (1.00 atm * 2.00 L) / (0.0821 L·atm/(mol·K) * 288 K)
n = 0.086 mol
To calculate the mass of propane, we need to use the molar mass of propane (C3H8), which is 44.10 g/mol.
Mass = n * molar mass
Mass = 0.086 mol * 44.10 g/mol
Mass ≈ 3.79 g
Therefore, the mass of propane in the flask is approximately 3.79 grams.
To find the mass of propane in the flask, we need to use the Ideal Gas Law equation: PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature in Kelvin.
First, let's convert the temperature from Celsius to Kelvin by adding 273.15.
T = 15°C + 273.15 = 288.15 K
Next, we can rearrange the Ideal Gas Law equation to solve for n, the number of moles:
n = PV / RT
We have:
P = 1.00 atm (pressure)
V = 2.00 L (volume)
R = 0.0821 L·atm/(mol·K) (ideal gas constant)
T = 288.15 K (temperature)
Now, let's substitute these values into the equation:
n = (1.00 atm * 2.00 L) / (0.0821 L·atm/(mol·K) * 288.15 K)
Calculating this expression will give us the number of moles of propane in the flask. Finally, to find the mass of propane, we need to multiply the number of moles by the molar mass of propane (C3H8), which is 44.10 g/mol.
Mass of propane = number of moles * molar mass
Use PV = nRT
Solve for n (remember T is in Kelvin).
Then n = grams/molar mass. Calculate grams.