algebra

posted by .

Not sure if I'm doing this right

Ln(3x-4)-Ln(x+1)=Ln(2)

My solution:
Ln 3x-4/x+1 =Ln2
3x-4/x+1=2/1
2x+2=3x-4
2=x-4
6=x

  • algebra -

    yes you are correct, but you must put brackets when typing in this format.
    On paper you probably extend the fraction bar over the (x+1) but the way you typed it, it would be understood as
    3x - 4/x + 1 as 3 separate terms on the left side

    check out this reply
    http://www.jiskha.com/display.cgi?id=1270500607

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. algebra 3-4

    im in a cal class but were reviewing algebra stuff now. and i have 1 more questions. it says. express the given quantity as a single loragithms 2ln4-ln2 so is it 2ln(2) please tell me if im getting the right answers and if im not then …
  2. Algebra 2

    Find the exact solution(s) of each system of equations?
  3. math

    i have this question and im not sure how to do it i keep getting stuck with these types of questions and i would appreciate some help (a) The rate of decay of a radioactive substance, S, is proportional to the amount remaining, x. …
  4. Calculus

    Find the second derivative of the following function: y=log(base2)x/x² y'=[(x/ln2)-2xlog(base2)x]/x^4 the derivative of x/ln2 is (ln2)^-1?
  5. MATH

    Find the solution of the given initial value problem. ty'+(t+1)y=t y(ln2)=0 t < 0
  6. Algebra II

    Did I do this correctly? Use log laws to write the following expression as a single logarithm. 3/2 ln25 + 3 ln2 = ln25 3/2 + ln2^3 = ln125 + ln2^3 =ln125 + ln8 =ln(125*8) =ln1000
  7. Algebra II-Please check

    Did I do this correctly? Use log laws to write the following expression as a single logarithm. 3/2 ln25 + 3 ln2 = ln25 3/2 + ln2^3 = ln125 + ln2^3 =ln125 + ln8 =ln(125*8) =ln1000
  8. Algebra 1

    Solve each system graphically. Be sure to check your solution. If a system has an infinite number of solutions, use set-builder notation to write the solution set.If a system has no solution, state this. I tried this and found no solution, …
  9. Calculus

    A is the doubling time for y=26e^0.5t, and B is the doubling time for y=13e^0.5t. Then (a) A=2B (b) B=2A (c) A=B (d) A=(ln2)B The correct answer is A, right?
  10. Math

    Find the zero of f(x) = (2^x-1)(-3^x+1). x = (ln2 + ln3)/(ln2 - ln3) x = (ln2 - ln3)/(ln2 + ln3) x = 2/(ln2 - ln3) x = - (ln5/ln1) I can't figure this out. Solve log(27)(log(x)10) = 1/3 for x. x = (3(inverse)sqrt90)/3 x = 10(inverse)sqrt3 …

More Similar Questions