What's the highest occupied molecular orbital of I-?

I'm really confused here, I thought you could only find for the first two rows of the periodic table.

You are correct that traditionally, the term "highest occupied molecular orbital" () is commonly used for the first two rows of the periodic table. However, this term can also be extended and used for elements beyond those rows.

To find the highest occupied molecular orbital of I- (Iodide ion), we need to look at the electronic configuration of the iodine atom (I) and then take into account the additional electron gained by the ion.

The atomic number of iodine is 53, which means it has 53 electrons in its neutral state. The electron configuration of iodine is [Kr]5s^24d^105p^5.

When iodine gains an electron to form the iodide ion (I-), it will have an additional electron in the 5p orbital, occupying the lowest energy level available.

So, for the iodide ion (I-), the highest occupied molecular orbital would be the 5p orbital, specifically the 5p^6 configuration.