Dirk pushes on a packing box with a horizontal force of 67.0 N as he slides it along the floor. The average friction force acting on the box is 3.00 N. How much total work is done on the box in moving it 3.10 m along the floor?
67*3.10 is the work done. Of that, 3*3.10 was done on the floor, the remainder was done on the box.
67-3 = 64 x 3.10 = 198
6. If you applied a force of 200N to push a box along the floor at a constant velocity, what is the net force on the box? What is the force of friction on the box?
To find the total work done on the box, we can use the formula:
Work = Force x Distance x Cosine(theta)
Where:
Force is the horizontal force applied by Dirk (67.0 N).
Distance is the distance the box is moved (3.10 m).
Cosine(theta) is the angle between the force applied and the direction of displacement. In this case, the force is applied horizontally, so the angle between the force and displacement is 0 degrees. The cosine of 0 degrees is 1.
Now, let's calculate the total work done:
Work = 67.0 N x 3.10 m x Cosine(0)
= 67.0 N x 3.10 m x 1
= 207.7 Joules
Therefore, the total work done on the box in moving it 3.10 m along the floor is 207.7 Joules.