Radon-22 has a half life of 4 days. If you begin with 32 grams of radon, how many grams will be left after 20 days?
20 days is 5 half-lives.
Divide 32 by two, five times.
That is the same as dividing 32 by 2^5.
thank you drwls for the help
To calculate how many grams of radon will be left after 20 days, you can use the formula for calculating exponential decay:
N(t) = N₀ * (1/2)^(t / T)
Where:
N(t) is the amount of radon remaining after time t
N₀ is the initial amount of radon (32 grams in this case)
t is the time elapsed (20 days)
T is the half-life of radon-22 (4 days)
Let's substitute the given values into the formula:
N(20) = 32 * (1/2)^(20 / 4)
Now, we can solve this equation to find the amount of radon remaining after 20 days.
N(20) = 32 * (1/2)^5
N(20) = 32 * 1/32
N(20) = 1 gram
Therefore, after 20 days, there will be approximately 1 gram of radon remaining.