Physics Problem 6.20

posted by .

The center of a 1.40 km diameter spherical pocket of oil is 1.50 km beneath the Earth's surface.


Estimate by what percentage g directly above the pocket of oil would differ from the expected value of g for a uniform Earth? Assume the density of oil is 8.0*10^2kg/m^3.

Express your answer using two significant figures.

  • Physics Problem 6.20 -

    Gravitational field= GMe/re^2-Mass/700^2 + G Massoil/700^2

    = 9.8N/kg+ G/700^2 (volumemhole)(densityoil-densityEarth)
    = 9.8+G/490000 * 4/3*PI*700^3 (800-6000)
    (I estimated Earth density at 6times that of water)
    = 9.8+6.67E-11/4900 (1.44E9)(-5200)
    =9.8-.12 or 9.7N/kg

    check all this.

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. Physics Problem 6.20

    The center of a 1.10 diameter spherical pocket of oil is 1.10 beneath the Earth's surface. Estimate by what percentage directly above the pocket of oil would differ from the expected value of for a uniform Earth?
  2. Physics

    The center of a 1.10km diameter spherical pocket of oil is 1.10km beneath the Earth's surface. Estimate by what percentage directly above the pocket of oil would differ from the expected value of for a uniform Earth?
  3. Phsyics

    The center of a 1.10km diameter spherical pocket of oil is 1.10km beneath the Earth's surface. Estimate by what percentage directly above the pocket of oil would differ from the expected value of for a uniform Earth?
  4. Physics

    The center of a 1.50 diameter spherical pocket of oil is 1.20 beneath the Earth's surface. Estimate by what percentage directly above the pocket of oil would differ from the expected value of for a uniform Earth?
  5. Physics

    The center of a 1.50 diameter spherical pocket of oil is 1.20 beneath the Earth's surface. Estimate by what percentage directly above the pocket of oil would differ from the expected value of for a uniform Earth?
  6. College Physics

    When searching for gold, measurements of g can be used find regions within the Earth where the density is larger than that of normal soil. Such measurements can also be used to find regions in which the density of the Earth is smaller …
  7. physics

    one liter (1000cm3) of oil is spiled onto a smooth lake. if the oil spreads out uniformly until it makes an oil slick justone molecure thick, with adjcent molecules just touching estimate the diameter of the oil slick. Assume the oil …
  8. physics

    Question 6) Oil and gas exploration companies find new underground deposits by measuring (with incredible precision) the value of g at the Earth's surface. EXTRA INFO GIVEN: The challenge: F=Gm1m2/r^2 ONLY works for two cases: point …
  9. physics

    The center of a 1.00km diameter spherical pocket of oil is 1.00kkm beneath the Earth's surface. Estimate by what percentage g directly above the pocket of oil would differ from the expected value of for a uniform Earth?
  10. physics

    In an experiment to estimate the diameter of an oil molecule,an oil drop of diameter 0.05cm spreads over a circular patch whose diameter is 20cm. ยก)determine the volume of the oil drop.

More Similar Questions