An objuect is located 20cm in front of a -3.00 lens where is the image?
To determine the location of the image formed by a lens, you can use the thin lens equation:
1/f = 1/do + 1/di
Where:
- f represents the focal length of the lens
- do represents the object distance (distance between the object and the lens)
- di represents the image distance (distance between the image and the lens)
In this case, the object distance (do) is given as 20 cm and the lens has a focal length (f) of -3.00 cm. The negative focal length indicates that it is a diverging lens.
Substituting these values into the equation, we have:
1/-3.00 = 1/20 + 1/di
We can solve this equation to find the value of di, which represents the image distance.
To do so, we can rearrange the equation:
1/di = 1/-3.00 - 1/20
Finding the common denominator and simplifying, we have:
1/di = (-20 - 3.00)/(-3.00 * 20)
Now, we can invert both sides of the equation:
di = (-3.00 * 20) / (-20 - 3.00)
Calculating this expression, we can determine the value of di, which represents the image distance.