Math
posted by David .
Find the value(s) of x, so that f’(x) = 0 for the function f(x) = 4x3 – 6x2 – 24x.

Math 
Reiny
I will assume you meant
f(x) = 4x^3 – 6x^2 – 24x
then
f'(x) = 12x^212x  24
= 0
divide by 12
x^2  x  2 = 0
(x2)(x+1) = 0
x = 2 or x = 1
Respond to this Question
Similar Questions

math a2
the expression 4x36x2 represents the area of a triangle. write the expression as the product of two factors. 4x36x2 as in: FOURx 3(power) (minus) SIXx 2(power) 
math a2
the expression 4x36x2 represents the area of a triangle. write the expression as the product of two factors. 4x36x2 as in: FOURx 3(power) (minus) SIXx 2(power) 
math a2
the expression 4x36x2 represents the area of a triangle. write the expression as the product of two factors. 4x36x2 as in: FOURx 3(power) (minus) SIXx 2(power) 
math a2
the expression 4x36x2 represents the area of a triangle. write the expression as the product of two factors. 4x36x2 as in: FOURx 3(power) (minus) SIXx 2(power) 
algebra
Did I do this problem the correct way if so is there a shorter way to explain this? 
math
Use polynomial long division to divide 4x3 + 24x2 – 24x + 4 by x2 – 5x + 1 
Math: Please check my answers
1. What is the degree of the monomial 3x2y3? 
Math
(6x4 – 3x + 5) – (3x4 + 4x3 – 6x2 + 1) 
algebra
Simplify: 30x^6 − 6x^3 + 24x/−6x2, x ≠ 0 
Math
Find the average value of the function over the given interval and all values of x in the interval for which the function equals its average value. f(x) = 4x3 − 3x2, [−1, 2]