Physics
posted by Adrianne .
You observe an arti cial satellite orbiting the earth and estimate it is at
an altitude h = [03] km above the earth's surface and has a mass
m = 3500 kg. You wish to calculate when the satellite will be back in the same position. From the second law of
motion and the gravitational force law, calculate the following:
(a) What is the satellite's velocity? (m/s)
(b) What is the period of the satellite's motion?
The only force acting on the satellite is the force of gravity (Fg) right? So by combining the two laws I have Fg = ma. I solved for Fg, but I need some pointers on where to go from there.

mass is m (it will not matter in the end)
if height above earth is h
then radius of orbit = r = Rearth + h
then
Fg = G m Mearth/r^2
a = v^2/r
so Fg = m v2/r
so
G m Mearth/r^2 = m v^2/r
note m cancels, feather drifts right beside the space station
G Mearth/r = v^2
there you go
get v then it goes 2 pi r at v
Respond to this Question
Similar Questions

physics
A satellite has a mass of 100 kg and is in an orbit at 2.00*10^6 m above the surface of the Earth (a) what is the potential enegry of the satellite at this location? 
physics
Two Earth satellites, A and B, each of mass m, are to be launched into circular orbits about Earth's center. Satellite A is to orbit at an altitude of 7460 km. Satellite B is to orbit at an altitude of 20500 km. The radius of Earth … 
physics
How much work is required to lift a 600kg satellite to an altitude of 4 * 10^6 m above the surface of the earth? 
physics
3. A satellite of mass 500 kg orbits the Earth with a period of 6000 s. The Earth has a mass of 5.98 x 1024 kg. (a) Calculate the magnitude of the Earth's gravitational force on the satellite. (b) Determine the altitude of the satellite … 
Physics
A satellite is orbiting the earth just above its surface. The centripetal force making the satellite follow a circular trajectory is just its weight, so its centripetal acceleration is about 9.81 m/s2 (the acceleration due to gravity … 
physics
A satellite is in a circular orbit around the Earth at an altitude of 3.30 106 m. (a) Find the period of the orbit. (Hint: Modify Kepler's third law so it is suitable for objects orbiting the Earth rather than the Sun. The radius of … 
SCTD
Physics a satellite orbiting 3.22 times 10 to the 5th power meters above the surface of the earth get the mass of the satellite is 3.80 times 10 to the 4th kilograms what is the weight or gravitational force exerted on the satellite … 
physics
NASA launches a satellite into orbit at a height above the surface of the Earth equal to the Earth's mean radius. The mass of the satellite is 550 kg. (Assume the Earth's mass is 5.97 1024 kg and its radius is 6.38 106 m.) (a) How … 
math
The orbital velocity of a satellite is given by v=√GM/R+h, where G= 6.67*10^11 Nm^2kg^2, is the Universal Gravitational Constant, M=6*10^24 kg, is the mass of Earth, R=6.38*10^3 km, the orbit of the satellite, and h is artificial … 
math
The orbital velocity of a satellite is given by v=√GM/R+h, where G= 6.67*10^11 Nm^2kg^2, is the Universal Gravitational Constant, M=6*10^24 kg, is the mass of Earth, R=6.38*10^3 km, the orbit of the satellite, and h is artificial …