posted by Anonymous .
Can you please someone check my answer for me? I don't know how to start thses answer. Chemistry is not my things. Please give me answers. :(
a)Determine the number of grams in 0.750 moles of the compound Iron(II)phosphate: Fe3(PO4)2.
b)How many atoms of iron are in 0.750 moles of the compound
And it will never be your thing if we give you the answers.
a. g = moles x molar mass Remember this one formula and you can rearrange it to give you three things, depending upon the question.
a. grams = moles x molar mass
b. moles = grams/molar mass
c. molar mass = grams/moles.
There is no chemistry involved. This is just a little algebra.
b. There are 6.022 x 10^23 molecules in a mole of anything so 0.75 x 6.022 x 10^23 = the number of molecules of iron(III) oxide. The formula for iron(III) oxide is Fe2O3. You know how many molecules are there and there are _______ atoms in 1 molecule of Fe2O3 so there are _____ in 0.75 mole Fe2O3.