How many moles of chlorine are needed to react with 3.30 moles of aluminum?
balance the reaction:
2Al + 3Cl2 >> 2AlCl3
so 3/2 moles of Cl2 for each mole of AL.
3/2 times 3.30?
and another question how many moles of product are formed in the reaction? thank you so much!
To determine the number of moles of chlorine needed to react with aluminum, we first need to know the balanced chemical equation for the reaction between chlorine and aluminum. Let's assume it is:
2Al + 3Cl2 → 2AlCl3
According to the balanced equation, 2 moles of aluminum react with 3 moles of chlorine gas (Cl2) to form 2 moles of aluminum chloride (AlCl3).
We are given that we have 3.30 moles of aluminum, so we need to determine the moles of chlorine needed.
Using the ratio from the balanced equation, we can set up a proportion to find the moles of chlorine:
(3.30 moles Al) / (2 moles Al) = (x moles Cl2) / (3 moles Cl2)
Cross-multiplying and solving for x:
3.30 moles Al * 3 moles Cl2 = 2 moles Al * x moles Cl2
9.90 moles Cl2 = 2x moles Cl2
Dividing both sides by 2:
x moles Cl2 = 9.90 moles Cl2 / 2
x ≈ 4.95 moles Cl2
Therefore, approximately 4.95 moles of chlorine are needed to react with 3.30 moles of aluminum.