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Determine the concentration of a dioxin solution whose percent absorbance is 0.40%
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Determine the concentration of a dioxin solution whose percent absorbance is 0.40%
This is the resulting: Absorbance Dioxin 0.64
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I am unfamiliar with an absorbance of 0.40%. 0.40, yes, but not the percent. If it really is 0.4%,
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A dioxin-contaminated water source contains 0.052% dioxin by mass. How much dioxin (in g) is present in 4.2 liters of this
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recall that density is mass over volume, or d = m/V substituting, 1 = m / 4200 m = 4200 g H2O to get
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...A dioxin-contaminated water source contains 0.044% dioxin by mass. How much dioxin is present in 6.5 L of this water? (Assume
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6500grms*.00044= XXXX grams Hint it is between 1 and 6 grams
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A standard solution with a FeSCN2+ concentration of 1.55x10^-4M has a percent transmittance (%T) of 18.8%. Another solution of
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To calculate the absorbance (A) of each solution, we can use the formula: A = -log10(%T/100) A)
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A standard solution with a FeSCN2+ concentration of 1.55x10^-4M has a percent transmittance (%T) of 18.8%. Another solution of
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A = log 1/T Use A1 = kc1. Substitute A1 and c1 and solve for k. Then A2 = kc2. Substitue A2 and k
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If you have an equation for a line, y = 0.15x + 0.010, where y is absorbance and x is concentration in molarity of Fe (2+),
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.065 = .15 x + .01 .15 x = .055 x = 5.5/15
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How would you get the concentration(ppm) of a sample from absorbance?
Absorbance of standard = 2.55 Absorbance of sample = 2.31
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Absorbance std = k*concn std 2.55 = k*8 Solve for k. Absorbance sample = k*concn sample 2.31 = k
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The standard solution of FeSCN2+ (prepared by combining 9.00 mL of 0.200 M Fe(NO3)3 w/1.00 mL of 0.0020 M KSCN) has an
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i think you have omitted part of the procedure but the following may get you started. For the
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The standard solution of FeSCN2+ (prepared by combining 9.00 mL of 0.200 M Fe(NO3)3 w/1.00 mL of 0.0020 M KSCN) has an
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Scroll down to the 25th question (authored by Amy) on this board, just below your post, and I
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The standard solution of FeSCN2+ (prepared by combining 9.00 mL of 0.200 M Fe(NO3)3 w/1.00 mL of 0.0020 M KSCN) has an
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To determine the equilibrium concentration of SCN- in this case, we can use the concept of Beer's
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