How many grams of CuSo4 x 5h20 to prepare 100 mL of a .10M solution?
How many moles do you want?
M x L = moles.
How many grams is that?
moles = grams/molar mass.
55.814
To calculate the number of grams of CuSO4 · 5H2O needed to prepare a 0.10 M solution in 100 mL, you need to follow these steps:
Step 1: Determine the molar mass of CuSO4 · 5H2O.
The molar mass of CuSO4 is:
Cu: 63.55 g/mol
S: 32.07 g/mol
O: 16.00 g/mol (four times)
Adding these masses together gives us:
63.55 + 32.07 + (16.00 × 4) = 159.61 g/mol
The molar mass of H2O is:
H: 1.01 g/mol (two times)
O: 16.00 g/mol
Adding these masses together gives us:
(1.01 × 2) + 16.00 = 18.02 g/mol
To calculate the molar mass of CuSO4 · 5H2O, we add the molar masses of CuSO4 and 5H2O:
159.61 + (18.02 × 5) = 249.33 g/mol
Step 2: Calculate the number of moles required.
We can use the equation:
Molarity (M) = moles/volume (L)
To rearrange it:
moles = Molarity × volume (L)
The volume is given as 100 mL, so we need to convert it to liters:
100 mL = 100/1000 L = 0.1 L
Substitute the values into the equation:
moles = 0.10 mol/L × 0.1 L = 0.01 mol
Step 3: Calculate the grams required.
To calculate the grams required, we can use the equation:
grams = moles × molar mass
Substitute the values into the equation:
grams = 0.01 mol × 249.33 g/mol = 2.49 g
Therefore, you will need 2.49 grams of CuSO4 · 5H2O to prepare a 0.10 M solution in 100 mL.
To determine the number of grams of CuSO4 x 5H2O needed to prepare a 0.10 M solution in 100 mL, we need to consider the molar mass and stoichiometry of the compound.
The molar mass of CuSO4 x 5H2O can be calculated by summing the atomic masses of its constituent elements. Copper (Cu) has a molar mass of approximately 63.55 g/mol, sulfur (S) has a molar mass of approximately 32.06 g/mol, oxygen (O) has a molar mass of approximately 16.00 g/mol, and hydrogen (H) has a molar mass of approximately 1.01 g/mol.
So, the molar mass of CuSO4 x 5H2O can be calculated as follows:
(63.55 g/mol + 32.06 g/mol + (16.00 g/mol * 4)) + ((1.01 g/mol * 2) * 5) = 249.68 g/mol
Now, we can calculate the number of moles required to prepare the solution:
0.10 mol/L * 0.100 L = 0.010 mol
We can convert this number of moles to grams by multiplying by the molar mass:
0.010 mol * 249.68 g/mol = 2.4968 g
Therefore, to prepare 100 mL of a 0.10 M solution of CuSO4 x 5H2O, we would need approximately 2.4968 grams of the compound.