Maths
posted by Felicity .
Alright, so I'm doing questions on exponent laws for my grade 11 math couse, and I came across one and I've no idea how to answer it. Could someone please explain step by step? According to textbook, answer should be 16:
(2^3) / [(2^0)(2^1)]
That "1" is a negative exponent in the last bit, just so you know.

Some of the exponential laws state that:
a^{0}=1
a^{1}=a
a^{b}=1/a^{b}
In your case, a=2 (the base).
So these laws should enable you to evaluate each term of the denominator.
The answer should indeed be 16.
I appreciate your having inserted sufficient parentheses to render the expression unambiguous. 
I hope I'm not asking too much, but it would be ace if you would type out the problem and the path to solving it just so I can compare and see where I'm going wrong?

Here it is. Post if help is needed.
(2^3) / [(2^0)(2^1)]
=8/(2^02^1)
=8/(1 1/2¹)
=8/(1 1/2)
=8/(1/2)
=16