a 125Newton box is pulled east along a horizontal surface with a force of 60Newton acting at an angle of 42degrees. if the force of friction on the box is 15 newton, what is the acceleration?
The pulling force component along the direction of motion is 60 cos42 = 44.6 N
Subtract 15N (backwards friction) from that to get the net force, F.
Then use F = m a = (W/g)*a
to solve for the acceleration, a.
You have use W/g for the mass because they gave you the weight of the box (W), not the mass (m).
m = 12.76 kg
a = 29.6 N/12.76 kg = ___ m/s^2