Consider a bowl containing 36 different slips of paper. Ten of the slips of
paper each contain one of the digits from the set 0 through 9 and 26 slips
each contain one of the 26 capital letters of the alphabet. If one slip is drawn
at random, what is P(slip contains a letter formed from straight�]line
segments only)?
A) 11/36 B) 15/26 C) 25/36 D) 15/36
You would have to count the letters which meet that criterion
based on how they were drawn.
If we base it on the font that is used have
A E F H I K L M N T V W X Y Z and
not B C D G J O P Q R S U
that's 15 you would add 15 plus 10 to get the answer of 15 out 36
To calculate the probability of drawing a slip containing a letter formed from straight-line segments only, we need to determine the number of slips that meet this criteria and divide it by the total number of slips in the bowl.
First, we need to figure out how many slips contain such letters.
Out of the 26 capital letters of the alphabet, there are 7 letters that can be formed using straight-line segments only: F, H, I, K, L, T, and Z.
Therefore, there are 7 slips that contain a letter formed from straight-line segments only.
Next, we need to determine the total number of slips in the bowl.
There are 10 slips that contain digits (0 through 9) and 26 slips that contain letters. So, the total number of slips is 10 + 26 = 36.
Now, we can calculate the probability by dividing the number of slips that meet the criteria (7) by the total number of slips (36):
P(slip contains a letter formed from straight-line segments only) = 7/36
Therefore, the correct answer is not provided in the options given.