math
posted by Dylan .
Would a drop of 40 Celsius degrees be more or less than a drop of 40 fahrenheit degrees? explain why
C = 5/9 (F  32)4032=8c
F = 9/5 C + 32 40+32=86f

look at the formula
F = (9/5) C + 32
each degree in C is roughly 2 units on the F scale
so a change of 40 C would be (9/5)(40) or 72 F
or
pick 2 readings which are appr. the same
20C is roughly equal to 70 F
drop each by 40 units
compare 20C with 30 F
20C is rather nasty cold even for us Canadians, while 30F is almost balmy.
What is your conclusion? 
It would be more of a drop. But i still done get the formula. did i do the formula right in the first place?

There is only one formula, one is merely the rearrangement of the other.
I don't know what you were trying to do.
A line like
C = 5/9 (F  32)4032=8c
makes no sense
What you are probably trying to do is find what
40 F is in C, and then what
0 F is in C
ok, if F=40, C = (5/9)(4032) = 4.44 C
if F = 0, C = (5/9)(032) =  17.78 C
So a change of 40 in F resulted in a change of (4.44(17.78)) or 22.22 C roughly 1/2 as noted above in my first reply 
Ok now that makes more sense to me. i must have typed it wrong. thank you.
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