Would a drop of 40 Celsius degrees be more or less than a drop of 40 fahrenheit degrees? explain why
C = 5/9 (F - 32)40-32=8c
F = 9/5 C + 32 40+32=86f
look at the formula
F = (9/5) C + 32
each degree in C is roughly 2 units on the F scale
so a change of 40 C would be (9/5)(40) or 72 F
or
pick 2 readings which are appr. the same
20C is roughly equal to 70 F
drop each by 40 units
compare -20C with 30 F
-20C is rather nasty cold even for us Canadians, while 30F is almost balmy.
What is your conclusion?
It would be more of a drop. But i still done get the formula. did i do the formula right in the first place?
There is only one formula, one is merely the rearrangement of the other.
I don't know what you were trying to do.
A line like
C = 5/9 (F - 32)40-32=8c
makes no sense
What you are probably trying to do is find what
40 F is in C, and then what
0 F is in C
ok, if F=40, C = (5/9)(40-32) = 4.44 C
if F = 0, C = (5/9)(0-32) = - 17.78 C
So a change of 40 in F resulted in a change of (4.44-(-17.78)) or 22.22 C roughly 1/2 as noted above in my first reply
Ok now that makes more sense to me. i must have typed it wrong. thank you.
To determine whether a drop of 40 degrees Celsius is more or less than a drop of 40 degrees Fahrenheit, we need to convert the temperatures to a common scale. The common scale we will use here is Celsius.
Let's convert a drop of 40 degrees Fahrenheit to Celsius using the conversion formula:
C = 5/9 (F - 32)
Plugging in the temperature:
C = 5/9 (40 - 32)
C = 5/9 (8)
C = 4.44 degrees Celsius (rounded to two decimal places)
Now, we compare the initial drop of 40 degrees Celsius to the converted drop of 4.44 degrees Celsius. Since 40 degrees Celsius is greater than 4.44 degrees Celsius, a drop of 40 degrees Celsius is more than a drop of 40 degrees Fahrenheit.
Therefore, a drop of 40 Celsius degrees is more than a drop of 40 Fahrenheit degrees.