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Calculate the enthalpy change for the following equation:
NO(g)+ 1/2O2(g) -----> NO2(g)

I have no clue how to do this. I just know the answer is supposed to be approximately -57.2 kJ. Can some explain to me what to do?

  • Chemistry -

    delta Hrxn = [delta H products] - [delta H reactants]
    Texts have a set of tables. Look up delta Hof for each and subtract the products - reactants to give delta H for the reaction. Elements in their standard state (O2 for example) are zero.

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