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If θ is an angle in standard position and its
terminal side passes through the point (−3,2), find
the exact value of cscθ .
I know the answer...but i want to know how you get the answer...

construct a triangle by drawing a perpendicular from the point (-3,2) to the x-axis.
by Pythagoras the hypotenuse is √(9+4) = √13

by definition cscθ = r/y = √13/2

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