math(advanced algebra&trigonometry)
posted by Rony .
If θ is an angle in standard position and its
terminal side passes through the point (−3,2), find
the exact value of cscθ .
I know the answer...but i want to know how you get the answer...
The answer is
radical 13/2

construct a triangle by drawing a perpendicular from the point (3,2) to the xaxis.
by Pythagoras the hypotenuse is √(9+4) = √13
by definition cscθ = r/y = √13/2
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