posted by Rony .
If θ is an angle in standard position and its
terminal side passes through the point (−3,2), find
the exact value of cscθ .
I know the answer...but i want to know how you get the answer...
The answer is
construct a triangle by drawing a perpendicular from the point (-3,2) to the x-axis.
by Pythagoras the hypotenuse is √(9+4) = √13
by definition cscθ = r/y = √13/2