Graph using the slope and the y-intercept.
x+5y=20.
Here is what I came up with:
5y=x(0)+20 5(0)= x+20
5y/5=20/5 x=20 (20,0)
y=4 (0,4)
The graph does not have a 20 on it. On the y axis it goes up to 10 and down to -10. On the x-axis it goes from 10 to -10 What did I do wrong?
5 y = -x + 20
y = (-1/5) x + 4
when x = 0, y = 4 (0,4) correct
slope is -1/5
from that point (0,4) go left one and up 5 to (-1,9)
or from (0,4) you could go right one and down 5 to (1,-1)
Thanks.
Just graph it do the work yourself. idiot.
To graph the equation "x+5y=20" using the slope and y-intercept method, you need to rewrite the equation in slope-intercept form "y = mx + b", where "m" represents the slope and "b" represents the y-intercept.
In this case, let's solve for "y":
x + 5y = 20
Subtract "x" from both sides:
5y = -x + 20
Divide both sides by 5:
y = (-1/5)x + 4
Now that we have the equation in slope-intercept form, we can determine the slope and y-intercept. The coefficient in front of "x" (-1/5) represents the slope, and the constant term (4) represents the y-intercept.
The slope is -1/5, which means that for every 1 unit increase in x, the y-coordinate decreases by 1/5 units. The y-intercept is 4, which indicates that the graph intersects the y-axis at the point (0, 4).
To graph the equation, start by plotting the y-intercept. In this case, the point (0, 4) represents the y-intercept. Then use the slope to find additional points and draw a line through them.
To find another point using the slope, you can choose any desired x-value. Let's say we choose x = 5:
y = (-1/5)(5) + 4 = -1 + 4 = 3
So, the point (5, 3) lies on the graph.
Plotting the two points (0, 4) and (5, 3) and drawing a line through them will give you the graph of the equation "x+5y=20".
It's important to note that the range of values you mentioned for the x-axis and y-axis (-10 to 10) is arbitrary. The range should be determined based on the data points you have and the scale you want to use for your graph.