physics
posted by Anonymous .
A bowling ball of mass 7.3 kg and radius 9.6 cm rolls without slipping down a lane at 3.4 m/s. Calculate its total kinetic energy. I tried this problem with the equation 3/4mv^2 but I did not get the correct answer, could I please get help with stepbystep explanation of how to get the correct equation to use.

The total KE is 7/10 M V^2. The rotational part is 1/5 M V^2, and the translational part is 1/2 MV^2.
Get the rotational KE from the moment of inertia (2/5)MR^2, KErot = (1/2) I w^2, and V = R w
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