posted by ALi .
How many grams of iron(III) nitrate.9H2O could be formed from the reaction of 3.676 g of iron with excess HNO3?
Please can u explain? i try balance the question i couldnt.
2Fe + 6HNO3 + 9H2O ==>2Fe(NO3)3.9H2O + 3H2
1. Write and balance the equation as above.
2. Convert 3.676 g Fe to moles. moles = grams/molar mass.
3. Using the coefficients in the balanced equation, convert moles Fe to moles of the product.
4. Now convert moles of the product to grams. g = moles x molar mass.
Check my work. Post your work if get stuck.
the answer is 11.17 or not