The sides of an rectangle was 5cm by 9cm. When both dimension were increased by an equal amounts the area of the rectangle increased by 120 cm^2 find the dimensions of the new rectangle.
What is 7/12 as a percent and decimal???
Divide 7 by 12 to get the decimal.
7/12=0.5833 (3 repeating)
Multiply by 100 to get percent.
58.33% (3 repeating)
Thank You Kathleen your a life saver
suppose that the height of an object shot straight up is given by
h=544t -16t^2. h= feet and t= seconds
Find the maximum height and the time at which the object hits the ground
To find the dimensions of the new rectangle, we need to set up and solve an equation based on the given information.
Let's denote the increase in both dimensions by 'x' (in cm). Therefore, the new length of the rectangle would be 5 cm + x, and the new width would be 9 cm + x.
The area of the original rectangle is given by length multiplied by width:
Area = Length × Width
Area = 5 cm × 9 cm = 45 cm^2
The area of the new rectangle is the original area increased by 120 cm^2:
New Area = Original Area + 120 cm^2
New Area = 45 cm^2 + 120 cm^2 = 165 cm^2
Now, we can set up an equation using the new dimensions and the new area:
New Length × New Width = New Area
(5 cm + x) × (9 cm + x) = 165 cm^2
Expanding the equation, we get:
45 cm^2 + 5 cm × x + 9 cm × x + x^2 = 165 cm^2
Simplifying and rearranging the equation:
x^2 + 14x + 45 = 165
x^2 + 14x - 120 = 0
Now, we need to solve this quadratic equation to find the value of 'x'. Factoring the equation or using the quadratic formula will give us the solutions for 'x'.
New rectangle has area of
(9+x)(5+x)
so ...
(9+x)(5+x) - 45 = 120
x^2 + 14x - 120 = 0
(x + 20)(x-6) = 0
x = -20 (silly) or x = 6
new rectangel is 11 by 15
check:
new rect. = 11x15 = 165
old rect. = 5x9 = 45
increase = 165-45 = 120 Checks!