What is the net ionic equation for the reaction of H2SO3 with Ba(OH)2?
2H^+(aq) + SO3^-2(aq) + Ba^+(aq) + 2OH^-(aq) ==> Ba(SO3(s) + H2O(l)
To write the net ionic equation for the reaction of H2SO3 (sulfurous acid) with Ba(OH)2 (barium hydroxide), we need to first write the balanced chemical equation.
The chemical equation for the reaction is:
H2SO3 + 2Ba(OH)2 → BaSO3 + 2H2O
Now, let's break down the equation into its respective ions:
H2SO3(aq) + 2Ba(OH)2(aq) → BaSO3(s) + 2H2O(l)
Next, we can write the ionic equation by separating the soluble ionic compounds into their respective ions:
2H+(aq) + SO3^2-(aq) + 2Ba^2+(aq) + 4OH^-(aq) → BaSO3(s) + 2H2O(l)
Lastly, we eliminate the spectator ions, which are the ions that appear on both sides of the equation and do not participate in the reaction. In this case, the spectator ions are Ba^2+ and OH^-:
2H+(aq) + SO3^2-(aq) → BaSO3(s) + 2H2O(l)
Therefore, the net ionic equation for the reaction of H2SO3 with Ba(OH)2 is:
2H+(aq) + SO3^2-(aq) → BaSO3(s) + 2H2O(l)
To determine the net ionic equation for the reaction of H2SO3 (sulfurous acid) with Ba(OH)2 (barium hydroxide), we first need to write the balanced chemical equation for the reaction.
The molecular equation for the reaction of H2SO3 with Ba(OH)2 is:
H2SO3 + Ba(OH)2 → BaSO3 + 2H2O
Now, let's break down the equation into ions to find the net ionic equation.
The compounds H2SO3 and Ba(OH)2 will dissociate into their respective ions when they are in an aqueous solution:
H2SO3 → 2H+ + SO3 2-
Ba(OH)2 → Ba2+ + 2OH-
Now, we can rewrite the balanced equation using the ions:
2H+ + SO3 2- + Ba2+ + 2OH- → BaSO3 + 2H2O
In the net ionic equation, we remove the spectator ions that appear on both sides of the equation. The spectator ions in this case are the Ba2+ and the SO3 2-.
Thus, the net ionic equation for the reaction of H2SO3 with Ba(OH)2 is:
2H+ + 2OH- → 2H2O