In triangle ABC, sin A = 0.7 and sin
B = 0.3 and side a = 12. What is the value of side b?
To find the value of side b in triangle ABC, we can use the law of sines. The law of sines states that the ratio of the length of a side to the sine of its opposite angle is constant for all sides in a triangle.
In this case, we are given sin A = 0.7 and sin B = 0.3. We are also given the length of side a = 12.
To apply the law of sines, we can use the following formula:
a / sin A = b / sin B
Plugging in the values we already know:
12 / 0.7 = b / 0.3
To find the value of b, we need to isolate it on one side of the equation. We can start by cross-multiplying:
12 * 0.3 = b * 0.7
3.6 = 0.7b
Next, we can divide both sides of the equation by 0.7 to solve for b:
b = 3.6 / 0.7
b ≈ 5.14
Therefore, the value of side b is approximately 5.14.
To find the value of side b, we can use the law of sines, which states that the ratio of the length of a side of a triangle to the sine of the opposite angle is constant.
Using the law of sines, we have:
sin A / a = sin B / b
Substituting in the given values, we have:
0.7 / 12 = 0.3 / b
To find the value of b, we can cross-multiply:
0.7 * b = 0.3 * 12
0.7b = 3.6
Now, we can solve for b by dividing both sides of the equation by 0.7:
b = 3.6 / 0.7
b ≈ 5.143
Therefore, the approximate value of side b is 5.143.