Post a New Question


posted by .

This is the equation for the formation of Al(OH)3:
6NaOH (aq) + Al2(SO4)3 (aq) ¨ 2Al(OH)3 (s) + 3Na2SO4 (aq)

Would any side products be formed if NaOH was added quickly into Al2(SO4)3?

  • Chemistry -

    I don't think so. If too much NaOH is added, the Al(OH)3 dissolves with the formation of Al(OH)4^-

  • Chemistry -

    chemistry is branch of sci

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

More Related Questions

Post a New Question