Chemistry

posted by .

This is the equation for the formation of Al(OH)3:
6NaOH (aq) + Al2(SO4)3 (aq) ¨ 2Al(OH)3 (s) + 3Na2SO4 (aq)

Would any side products be formed if NaOH was added quickly into Al2(SO4)3?

  • Chemistry -

    I don't think so. If too much NaOH is added, the Al(OH)3 dissolves with the formation of Al(OH)4^-

  • Chemistry -

    chemistry is branch of sci

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. Chemistry

    so if the equation I'm using is 3CuSO4+2AL(NO3)3 arrow 3CU(NO3)2+Al2(SO4)3 how many moles of CuSO4 would be needed to produce 8 moles of Al2(SO4)3?
  2. Chemistry

    Why is heating required for this formation: 6NaOH (aq) + Al2(SO4)3 (aq) ¨ 2Al(OH)3 (s) + 3Na2SO4 (aq)?
  3. chemistry

    A sample of aluminum sulfate 18-hydrate, Al2(SO4)3 · 18 H2O, containing 157.0 mg is dissolved in 1.000 L of solution. Calculate (a) molarity of Al2(SO4)3 (b) molarity of SO42- (c) molality of Al2(SO4)3, assuming that the density of …
  4. chemistry

    Hi, the question is: in each reaction, identify what have been oxidised and reduced. The equation is: 2Al + 3H2SO4 ---> Al2(SO4)3 + 3H2 I am confused about the Al2(SO4)3 I know what oxides and reductions us I just don't understant …
  5. chemistry

    consider the reaction, 2Al(OH)3+3H2SO4---->Al2(SO4)3+6H2O a. Given that 152g of H2SO4 reacts with 234g of Al(OH)3 Howmany grams of Al2(SO4)3 will be theoretical generated?
  6. Chemistry

    For the following reaction: Al2(SO4)3 + 6NaOH = 2Al(OH)3 + 3Na2SO4 How many moles of Na2SO4 can be made with 3.2 moles of NaOH and excess Al2(SO4)3?
  7. Chemistry

    How many grams of aluminum sulfate, Al2( SO4)3 , will be formed from 0.98 g of sulfuric acid and enough aluminum according to the following reaction: H2SO4 + Al -> Al2(SO4)3 + H2
  8. chemestiry

    Al2(SO4)3(aq) + BaCl2(aq) BaSO4(s) + AlCl3(aq) Consider the unbalanced equation above. A 0.680 g sample of impure Al2(SO4)3 reacts with excess BaCl2. If the sample produces 0.530 g of BaSO4, what is the mass percent of Al2(SO4)3 in …
  9. chemestiry

    Al2(SO4)3(aq) + BaCl2(aq) BaSO4(s) + AlCl3(aq) Consider the unbalanced equation above. A 0.680 g sample of impure Al2(SO4)3 reacts with excess BaCl2. If the sample produces 0.530 g of BaSO4, what is the mass percent of Al2(SO4)3 in …
  10. chemestiry

    Al2(SO4)3(aq) + BaCl2(aq) BaSO4(s) + AlCl3(aq) Consider the unbalanced equation above. A 0.680 g sample of impure Al2(SO4)3 reacts with excess BaCl2. If the sample produces 0.530 g of BaSO4, what is the mass percent of Al2(SO4)3 in …

More Similar Questions