container A has twice the capicity of container B. container A is full of sand and container B is empty. suppose 1/8 of the sand in container A is poured into container B. what fractional part of container B will conatin sand.........please halpme i am confused
To find the fractional part of container B that will contain sand, we first need to determine the ratio of the amount of sand poured into container B to the total capacity of container B.
Let's break down the problem step by step:
1. Let's assume the capacity of container B is represented by "x".
2. We are given that container A has twice the capacity of container B, so the capacity of container A is "2x".
3. Next, we are told that 1/8 of the sand in container A is poured into container B.
4. To find the fraction of sand poured from container A into container B, we need to divide the amount of sand poured (1/8) by the total amount of sand in container A.
5. Since container A is full of sand, the total amount of sand in container A is 1. Therefore, the fraction of sand poured into container B is 1/8.
6. Now, let's find the capacity of container B that will contain this fraction of the sand. We can do this by multiplying the fraction (1/8) by the capacity of container B (x).
(1/8) * x = x/8
7. Therefore, the fractional part of container B that will contain sand is x/8.
In conclusion, after pouring 1/8 of the sand from container A into container B, container B will have x/8 of its capacity filled with sand.