algebra
posted by michelle .
How would u solve
D\d+2  2\2d = d+6\ d^24
I got to
D(d2)(2d) 2 (d+2)(d2)=2dd^2+126d
How would you solve? Im confused

Did you not notice that the denominator of the right side is (d2)(d+2) ?
I will also assume that D is really d, or else you have 2 unknowns.
so let's rewrite ...
d/(d+2)  2/(2d) = (d+6)/[(d+2)d2)]
d/(d+2) + 2/(d2) = (d+6)/[(d+2)d2)]
now multiply each term by (d+2)(d2)
d(d2) + 2(d+2) = d+6
d^2  2d + 2d + 4 = d + 6
d^2  d  2 = 0
(d2)(d+1) = 0
d = 2 or d = 1
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